(x^2+10/48)=(x+10/48)

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Solution for (x^2+10/48)=(x+10/48) equation: 



(x^2+10/48)=(x+10/48)

We move all terms to the left:

(x^2+10/48)-((x+10/48))=0

We add all the numbers together, and all the variables

(x^2+10/48)-((+x+10/48))=0

We get rid of parentheses

x^2-((+x+10/48))+10/48=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$

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